-0.02x^2+x+5.75=0

Solution for -0.02x^2+x+5.75=0 equation:

-0.02x^2+x+5.75=0

a = -0.02; b = 1; c = +5.75;
Δ = b2-4ac
Δ = 12-4·(-0.02)·5.75
Δ = 1.46
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.46}}{2*-0.02}=\frac{-1-\sqrt{1.46}}{-0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.46}}{2*-0.02}=\frac{-1+\sqrt{1.46}}{-0.04}
$